phenomenon

black hole evaporation

Quantum process where black holes lose mass and eventually vanish through Hawking radiation.
35 related articles · 2 formulas

Description

Black hole evaporation is the quantum mechanical process by which a black hole loses mass and energy over time, eventually disappearing entirely. This process is driven by Hawking radiation, a form of thermal radiation predicted to be emitted from the event horizon due to quantum effects. The smaller the black hole, the hotter it radiates and the faster it evaporates, leading to a runaway process in the final moments. This concept is central to the intersection of general relativity and quantum mechanics, and it raises deep questions about information loss and the nature of spacetime.

History

The process was predicted by Stephen Hawking in 1974, building on earlier work by Jacob Bekenstein on black hole thermodynamics. Hawking's calculation showed that black holes are not truly black but emit radiation, a result that transformed theoretical physics.

How it works

In quantum field theory, the vacuum is not empty but filled with virtual particle-antiparticle pairs that constantly appear and annihilate. Near a black hole's event horizon, the intense gravitational field can separate such a pair before they annihilate: one particle falls into the black hole (with negative energy) while the other escapes as real radiation. The infalling negative-energy particle reduces the black hole's mass, while the escaping particle carries away energy. Over time, this leakage causes the black hole to shrink, and as it shrinks, its temperature rises, accelerating the process until the black hole ends in a final burst of radiation.

In practice

While no black hole has been observed to evaporate (stellar-mass black holes are too cold), primordial black holes—if they exist—could be small enough to evaporate within the universe's lifetime, and their final explosions might be detectable as gamma-ray bursts or gravitational wave signals.

Fun fact

A black hole with the mass of Mount Everest would evaporate in about a second, releasing energy equivalent to a large nuclear bomb.

Concept graph →

Formulas

$$\tau_{BH} \propto M_{BH}^3$$
Time for a black hole to evaporate via Hawking radiation.
What is in the formula
\tau_{BH}variableEvaporation time of the black hole — time second
M_{BH}variableMass of the black hole — mass kilogram
τ_{bh}\approx160(\frac{m_{bh}}{10^{10}{г}})^3{сек} · 2606.03316v2
$$M(t) = M_0 \left(1 - \frac{t}{\tau}\right)^{1/3}$$
Black hole mass decreases as cube root of time during Hawking evaporation.
What is in the formula
MvariableBlack hole mass at time t — mass kilogram
M_0variableInitial black hole mass — mass kilogram
tvariableTime since start of evaporation — time second
τvariableTotal evaporation timescale — time second
1 - t/τoperatorComputes the fraction of remaining lifetime — linear combination
( )^{1/3}operatorTakes the cube root of the remaining fraction — cube root
m(t)=m_0(1-\frac{t}{τ_h})^{1/3} · 2607.16880v1

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