law

Wien's displacement law

Wien's displacement law states that the peak wavelength of blackbody radiation is inversely proportional to its temperature.
8 related articles · 5 formulas · 2 who worked here

Description

Imagine you are heating a piece of metal. At first it’s dark, then red, then yellow, and even blue. Wien's displacement law explains how the color of the glow depends on temperature: the hotter the body, the shorter (bluer) the waves it emits. It is as if you move a color slider on a screen: more heat — go to blue, less — to red. The formula is simple: λ_max × T = constant, where λ_max is the wavelength at which most light is emitted, and T is the temperature in Kelvin.

History

At the end of the 19th century, the radiation spectrum of heated bodies was actively studied experimentally. Wilhelm Wien, relying on ideas of adiabatic compression of radiation in a cavity, showed that the product of temperature and the wavelength of the maximum should be constant. He came to this conclusion in 1893, and in 1896 he proposed an empirical formula for the energy distribution in the spectrum. These works stimulated Max Planck to discover quantization, and in 1911 Wien was awarded the Nobel Prize. The law played a key role in the formation of quantum physics and later found application in astrophysics: Edwin Hubble used it to study stars and galaxies.

How it works

Wien's displacement law is applicable to black-body radiation and holds well for many astronomical objects (stars, star clusters). It allows estimating a star's temperature from the color of its radiation with good accuracy if interstellar absorption is small. It is also used in optical pyrometry for non-contact measurement of high temperatures in metallurgy and glassmaking. Boundary conditions: the law is accurate only for black bodies or gray bodies with non-selective radiation; in real objects, especially gases, line radiation distorts the spectrum, and the maximum may shift.

Fun fact

Thanks to this law, astronomers determine the temperature of stars by their color! Bluish stars are hotter than red ones — like a gas burner flame: blue flame is hotter than yellow. The most famous star, the Sun, with a surface temperature of about 5800 K, shines in the yellow-green range, which gives us the maximum light precisely in the visible part of the spectrum — not by chance, but according to Wien's law.

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Formulas

$$\lambda_{\rm max} = \frac{b}{T}$$
The peak wavelength of blackbody radiation is inversely proportional to temperature.
What is in the formula
lambda_maxvariableWavelength at which blackbody emission is maximum — wavelength metre
TvariableAbsolute temperature of the blackbody — temperature kelvin
bconstantWien's displacement constant, relating peak wavelength to temperature — wien displacement constant = 2.897771955e-3 metre kelvin
λ_{\rmmax}=\frac{b}{t} · 2606.30750
$$\lambda_{\text{max}} T = b$$
Peak wavelength of blackbody radiation is inversely proportional to temperature.
What is in the formula
\lambda_{\text{max}}variableWavelength of maximum spectral radiance — wavelength metre
TvariableAbsolute temperature of the blackbody — temperature kelvin
bvariableWien's displacement constant — wien displacement constant metre kelvin
bconstantWien's displacement constant, relating peak wavelength to temperature — wien displacement constant = 2.897771955e-3 metre kelvin
λ_{{max}}=\frac{b}{t} · 2607.06684
$$T \propto \left(\frac{1}{\tau}\right)^{1/4}$$
Temperature decreases as time to the -1/4 power.
What is in the formula
Tvariabletemperature — temperature kelvin
τvariabletime since start of cooling — time second
t(τ)\approx(\frac{\etagm_p^2}{2τ4πr_p^3εσ})^{1/4} · 2607.02653v1
$$L = 4\pi R^2 \sigma T^4$$
Luminosity relates to radius and temperature.
What is in the formula
LvariableLuminosity (total power radiated) — luminosity watt
RvariableRadius of the radiating body — radius metre
TvariableEffective temperature of the surface — temperature kelvin
\sigmaconstantProportionality constant relating blackbody radiated power to temperature — stefan boltzmann constant = 5.670374419e-8 watt per metre squared per kelvin to the fourth
r=\sqrt{\frac{l}{4πσt^4}} · 2606.06575v1
l=4πr^2σt^4 · 2606.28993
l=4πr^2σt^4 · 2606.29435
l=4πr^2σt^4 · 2607.06684
$$B_\nu(T) = \frac{2h\nu^3}{c^2} \frac{1}{e^{h\nu/k_B T} - 1}$$
Describes spectral radiance of blackbody radiation.
What is in the formula
B_νvariableSpectral radiance per unit frequency — spectral radiance watt per metre squared per steradian per
νvariableFrequency of radiation — frequency hertz
TvariableAbsolute temperature of blackbody — temperature kelvin
hconstantPlanck constant, relating energy of a photon to its frequency — planck constant = 6.62607015e-34 joule second
cconstantSpeed of light in vacuum, fundamental constant — speed of light = 299792458 metre per second
k_BconstantBoltzmann constant, relating temperature to energy — boltzmann constant = 1.380649e-23 joule per kelvin
νi_ν=\frac{2hν^4}{c^2}\frac{1}{\exp(hν/k_bt)-1} · 2607.14276

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