theorem

equipartition theorem

The equipartition theorem states that energy is equally distributed among all degrees of freedom in thermal equilibrium.
28 related articles · 6 formulas · 2 who worked here

Description

The idea of energy equipartition was formulated in the 19th century by James Maxwell and Ludwig Boltzmann. They realized that if particles in a gas collide billions of times per second, the energy must be evenly spread over all degrees of freedom – thus any preference is quickly erased. This is like a fair division of a pie: all possible motions receive exactly half of a small portion of heat – ½ kT per each, where k is Boltzmann's constant and T is temperature. For a gas of monatomic molecules (argon, neon), the heat capacity turns out to be exactly 3 calories per mole per kelvin.

History

The roots of the theorem lie in the work of James Clerk Maxwell on the kinetic theory of gases (1860s). Maxwell showed that in a dilute gas, the average kinetic energy of translational motion of a particle is 3kT/2. Later, Ludwig Boltzmann generalized this result to any quadratic energy forms using his statistical approach. He also connected this regularity with the distribution over states (Boltzmann distribution). In the 1870s, rigorous proofs were obtained within the framework of classical statistical mechanics. Later it became clear that the theorem is valid only in the classical limit; at low temperatures, quantum refinement is required.

How it works

The theorem is widely used for calculating heat capacities of gases and solids in the classical limit, for estimating the energy of thermal motion in molecular dynamics simulations, and as a check of the correctness of numerical models. However, it ceases to work when the thermal energy kT becomes comparable to the spacing between quantum levels – then quantum statistics come into play.

In practice

Explains the heat capacity of gases: why heating a liter of helium requires less heat than a liter of water vapor. Underlies the design of cooling systems and engines.

Fun fact

The theorem works excellently for light gases at room temperature, but breaks down under strong cooling: quantum effects 'freeze out' rotations and vibrations, and the substance behaves as if it has fewer energy piggy banks.

Concept graph →

Formulas

$$\frac{dE_{\text{heat}}}{dt} \le \frac{dE_{\text{cool}}}{dt}$$
Heating rate cannot exceed cooling rate.
What is in the formula
E_heatvariableHeat energy added to system — energy joule
E_coolvariableHeat energy removed from system — energy joule
tvariableTime — time second
d/dtoperatorRate of change with respect to time — time derivative
\frac{de_{{heat}}}{dt}\le\frac{de_{{rad}}}{dt} · 2607.15028
$$E = m c^2$$
Energy equals mass times the speed of light squared.
What is in the formula
EvariableEnergy — energy joule
mvariableMass — mass kilogram
cconstantUniversal constant representing the maximum speed at which information and energy can travel — speed of light = 299792458 metre per second
$e_γ\approxm_{dm}c^2$ · 2604.00579
e=mc^2 · 2607.21719v1
$$f\frac{\partial u}{\partial z} = -\frac{g}{\Theta_0} \frac{\partial \Theta}{\partial y}$$
Relates vertical wind shear to horizontal temperature gradient.
What is in the formula
uvariablezonal wind component — velocity metre per second
zvariablevertical coordinate — length metre
Θvariablepotential temperature — temperature kelvin
yvariablemeridional coordinate — length metre
fconstantCoriolis parameter, twice the planetary rotation rate times sine of latitude — coriolis parameter = 1.458e-4 per second
gconstantstandard acceleration due to gravity at Earth's surface — gravitational acceleration = 9.80665 metre per second squared
Θ₀constantconstant reference potential temperature of the background state — reference potential temperature = 300 kelvin
∂/∂zoperatorvertical derivative — partial derivative
∂/∂yoperatormeridional derivative — partial derivative
r\sinθ\frac{\partialω^2}{\partialz}=\frac{g}{\theta_0r}\frac{\partial\theta}{\partialθ} · 2607.19730v1
$$\frac{1}{2} m \sigma_v^2 = \frac{3}{2} k T$$
Kinetic energy per particle equals thermal energy per particle.
What is in the formula
mvariableMass of a particle — mass kilogram
\sigma_vvariableVelocity dispersion (standard deviation of particle velocities) — velocity dispersion metre per second
TvariableTemperature — temperature kelvin
kconstantBoltzmann constant, relates temperature to energy — boltzmann constant = 1.380649e-23 joule per kelvin
f_{\rmnth}=\frac{μm_pσ_v^2}{kt} · 2607.24911v1
$$\frac{d\epsilon}{dn} = \frac{\epsilon + p}{n}$$
The energy gradient per particle equals enthalpy per particle.
What is in the formula
\epsilonvariableenergy density — energy density joule per cubic metre
nvariableparticle number density — number density per cubic metre
pvariablepressure — pressure pascal
\frac{d}{dn}operatorderivative with respect to particle number density — derivative with respect to number density
\frac{dε}{dn}=\frac{ε+p}{n} · 2605.08584v2
$$R_B = rac{2GM}{c_s^2}$$
Radius where gravitational energy equals thermal energy.
What is in the formula
R_BvariableBondi radius — radius metre
Mvariablemass of the central object — mass kilogram
c_svariablesound speed of the surrounding medium — sound speed metre per second
GconstantUniversal constant of gravitation — gravitational constant = 6.67430e-11 cubic metre per kilogram per second squared
r_b=\frac{2gm_{bh}}{c_s^2} · 2606.02700v1

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