law

Kepler's third law

Kepler's third law states that the square of a planet's orbital period is proportional to the cube of its semi-major axis.
7 related articles · 1 formulas · 4 who worked here

Description

Imagine planets are skaters on a huge rink: the farther from the center, the larger the circles and the longer a lap takes. So in space: the farther a planet from the Sun, the longer its 'year.' Kepler's third law relates distance and orbital time with a simple formula: the square of the period is inversely proportional to the cube of the distance. It's as if you knew the rink's radius and could predict how long a skater takes to complete a full circle!

History

Johannes Kepler, working with the precise data of Tycho Brahe, discovered the law in 1619 and published it in 'Harmony of the World.' Half a century later, Isaac Newton theoretically derived all three laws from the law of universal gravitation. In the 20th century, the law became key to discovering exoplanets: by measuring the periodicity of transits, astronomers compute the planets' distance to their star.

How it works

Used to determine masses of celestial bodies in binary systems, distances to exoplanets, and calculation of satellite orbits. Within the Solar System, accuracy is extremely high; however, near massive compact objects (neutron stars, black holes) relativistic corrections are needed, and when more than two bodies are present, numerical integration is required.

Fun fact

Astronomers use this law to find planets around other stars! When a planet passes in front of a star, we see a mini-eclipse, and from the duration and period we can calculate the distance to the star.

Concept graph →

Formulas

$$P = 2\pi \sqrt{\frac{a^3}{GM}}$$
Orbital period squared is proportional to semi-major axis cubed.
What is in the formula
Pvariableorbital period — period second
avariablesemi-major axis of the orbit — length metre
Mvariablemass of the central body — mass kilogram
Gconstantconstant of universal gravitation — gravitational constant = 6.67430e-11 cubic metre per kilogram per second squared
sqrtoperatortakes the square root — square root
p\approx2π\sqrt{\frac{r^3}{gm}} · 2605.04631v1
ω_p=\sqrt{\frac{(1+e)gm_\bullet}{r_p^3}} · 2606.02692v1
\frac{a^3}{p^2}=\frac{g(m_s+m_p)}{4π^2} · 2606.23774
p^2=\frac{4π^2a^3}{g(m_{wd}+m_{don})} · 2606.28993

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